C. 24 mm, 24 mm, 24 mm

A circular gift has a 4.75 inch radius. alyssa wants to wrap a ribbon that costs $0.50 per inch around the gift. How much money

Montano1993 [528]

The Alyssa will spend $14.915 for wrap a ribbon around the gift, if a ribbon costs $0.50 per inch.

Step-by-step explanation:

The given is,

A circular gift has a 4.75 inch radius

Ribbon that costs $0.50 per inch

Step:1

Formula to calculate the perimeter of circle,

$Perimeter, P = 2\pi r$ ......................(1)

Where, r - Radius of circle

From the given,

r = 4.75 inches

Equation (1) becomes,

$P = 2 (\pi )(4.75)$

$= 2(3.14)(4.75)$ (∵ $\pi$ = 3.14)

$=2(14.915)$

$=29.83$

Perimeter, P = 29.83 inches

Step:2

Cost for wrap the ribbon to around the circular gift,

= Perimeter of circular gift × ribbon cost per inch

= (29.83 × 0.50)

= $14.915

Cost for wrap the ribbon to around the circular gift = $14.915

Result:

The Alyssa will spend $14.915 for wrap a ribbon around the gift, if a ribbon costs $0.50 per inch.

7 0

3 years ago

Select all expressions that are equal to 3 1/4.

Ad libitum [116K]

26*1/8=13/4
1/8 ×2=1/4
4×13=52
1/4×3=3/4
13×1/4=3/14

I'd say the answer is none

6 0

3 years ago

**Spam answers will not be tolerated**

Morgarella [4.7K]

Answer:

$f'(x)=-\frac{2}{x^\frac{3}{2}}$

Step-by-step explanation:

So we have the function:

$f(x)=\frac{4}{\sqrt x}$

And we want to find the derivative using the limit process.

The definition of a derivative as a limit is:

$\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Therefore, our derivative would be:

$\lim_{h \to 0}\frac{\frac{4}{\sqrt{x+h}}-\frac{4}{\sqrt x}}{h}$

First of all, let's factor out a 4 from the numerator and place it in front of our limit:

$=\lim_{h \to 0}\frac{4(\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x})}{h}$

Place the 4 in front:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}$

Now, let's multiply everything by (√(x+h)(√(x))) to get rid of the fractions in the denominator. Therefore:

$=4\lim_{h \to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt x}}{h}(\frac{\sqrt{x+h}\sqrt x}{\sqrt{x+h}\sqrt x})$

Distribute:

$=4\lim_{h \to 0}\frac{({\sqrt{x+h}\sqrt x})\frac{1}{\sqrt{x+h}}-(\sqrt{x+h}\sqrt x)\frac{1}{\sqrt x}}{h({\sqrt{x+h}\sqrt x})}$

Simplify: For the first term on the left, the √(x+h) cancels. For the term on the right, the (√(x)) cancel. Thus:

$=4 \lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }$

Now, multiply both sides by the conjugate of the numerator. In other words, multiply by (√x + √(x+h)). Thus:

$= 4\lim_{h\to 0}\frac{\sqrt x-(\sqrt{x+h})}{h(\sqrt{x+h}\sqrt{x}) }(\frac{\sqrt x +\sqrt{x+h})}{\sqrt x +\sqrt{x+h})}$

The numerator will use the difference of two squares. Thus:

$=4 \lim_{h \to 0} \frac{x-(x+h)}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Simplify the numerator:

$=4 \lim_{h \to 0} \frac{x-x-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}\\=4 \lim_{h \to 0} \frac{-h}{h(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Both the numerator and denominator have a h. Cancel them:

$=4 \lim_{h \to 0} \frac{-1}{(\sqrt{x+h}\sqrt x)(\sqrt x+\sqrt{x+h})}$

Now, substitute 0 for h. So:

$=4 ( \frac{-1}{(\sqrt{x+0}\sqrt x)(\sqrt x+\sqrt{x+0})})$

Simplify:

$=4( \frac{-1}{(\sqrt{x}\sqrt x)(\sqrt x+\sqrt{x})})$

(√x)(√x) is just x. (√x)+(√x) is just 2(√x). Therefore:

$=4( \frac{-1}{(x)(2\sqrt{x})})$

Multiply across:

$= \frac{-4}{(2x\sqrt{x})}$

Reduce. Change √x to x^(1/2). So:

$=-\frac{2}{x(x^{\frac{1}{2}})}$

Add the exponents:

$=-\frac{2}{x^\frac{3}{2}}$

And we're done!

$f(x)=\frac{4}{\sqrt x}\\f'(x)=-\frac{2}{x^\frac{3}{2}}$

5 0

2 years ago

K is the midpoint of VW. If KV = 3x and KW = 5x-10, what is VW? 22.5 15 7.5 30

LekaFEV [45]

Answer:

15

Step-by-step explanation:

just took the test. x=5 and the answer to the equation is 15

5 0

2 years ago

What is the sum of the 12th square number and the 6th square number?

aleksklad [387]

Answer:

180

Step-by-step explanation:

The 12 th square number is

12² = 12 × 12 = 144

The 6 th square number is

6² = 6 × 6 = 36

Thus

sum = 144 + 36 = 180

5 0

2 years ago