Pythagoras theorem ! (a²+b²=c²)
Q1) AC = √4.8²+3.6²
= √36
= 6cm
Q2) AB= √17.55² - 6.75²
= √262.44
= 16.2cm
Q3) BC= √14² - 6²
= √160
= 12.64911
= 12.6 cm (to 3sf)
I’m assuming what you’re asking here is how to *factor* this expression. For that, let’s rearrange the expression into a more familiar form:
-c^2-4c+21
From here, we’ll factor out a -1 so that we have:
-(c^2+4c-21)
Let’s focus on the quadratic expression inside the parentheses. To find our factors (c + x)(c + y), we’ll need to find two terms x and y that multiply together to make -21 and add together to make 4. It turns out that the numbers -3 and 7 work out perfectly for that purpose (-3 x 7 = -21 and 7 + (-3) = 4), so substituting them in for x and y, we have:
(c + (-3))(c + 7)
(c - 3)(c + 7)
And adding back on the negative from a few steps earlier:
-(c - 3)(c + 7)
The answer is 3 1/4 if I'm correct
Answer:
8/9 sorry if wrong
Step-by-step explanation:
