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3 years ago

On a piece of paper, use a protractor to construct a triangle with angle measures of 30° and 40°.

Mathematics

2 answers:

vova2212 [387]3 years ago

6 0

Step-by-step explanation:

The answer is b. an obtuse. This is because if it were a right-angled triangle, then 90 + 30 + 40 would equal 180 and it doesn't. It's obtuse because 30 + 40 = 70, and triangles have to add up to 180° so the last angle would need to be 110°, which is an obtuse angle. I hope this helps!

tatyana61 [14]3 years ago

3 0

An angle smaller than 90° is gonna be a acute so your answer is gonna be acute

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olga55 [171]

Answer:

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Step-by-step explanation:

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777dan777 [17]

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

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$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$