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DerKrebs [107]
3 years ago
13

Briana bought 3 bottles of ketchup and 2 bottles of mustard and for $11.85. Logan bought 2 bottles of ketchup and 5 bottles of m

ustard for $13.73. Find the cost of each.
Mathematics
1 answer:
zheka24 [161]3 years ago
3 0
<h2>Answer:</h2><h2>The cost of ketchup bottle, x = 2.89</h2><h2>The cost of mustard bottle, y = 1.59</h2>

Step-by-step explanation:

Let the ketchup be represented as x and mustard as y

Briana  bought 3 bottles of ketchup and 2 bottles of mustard and for $11.85

3x + 2y = 11.85 ...(1)

Logan bought 2 bottles of ketchup and 5 bottles of mustard for $13.73.

2x + 5y = 13.73 ...(2)

Multiplying eq (1) by 2, we get

6x + 4y = 23.7 ...(3)

Multiplying eq (2) by 3, we get

6x + 15y = 41.19 ...(4)

Subtracting eq (3) from (4),

we get 11y = 17.49

y = 1.59, substitute it in eq(1), we get

x = 2.89

Therefore, the cost of ketchup bottle, x = 2.89

The cost of mustard bottle, y = 1.59

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Kelly’s baby brother weighs 7.71 is pounds. Her newborn kitten weighs 0.24 pound. How much more does kelly’s baby brother weigh
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7.47

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Which of the following would be a good reason to place your money into a savings account?
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One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
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liubo4ka [24]

Answer:

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Step-by-step explanation:

To find the mean of this demand distribution;

Mean = Expected vale = E[x]

for discrete provability function,

we say E[x] = ∑(x.p(x))

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∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )

∑(x.p(x)) = 100

7 0
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