All categories

2 years ago

Question 1

Mathematics

1 answer:

storchak [24]2 years ago

5 0

Answer:

x = 13.5

y = 7

(13.5,7)

what the solution means is that (13.5,7) would be the point at which the two lines, x+y=20.5 and x-y=6.5, would intersect

Step-by-step explanation:

x + y = 20.5

x - y = 6.5

if we add the two equations we get:

2x = 27

x = 13.5

y = 20.5 - 13.5

y = 7

solution as an ordered pair:

(13.5,7)

What the solution means is that (13.5,7) would be the point at which the two lines, x+y=20.5 and x-y=6.5, would intersect

You might be interested in

1/6×2/3 show me how to do it

hodyreva [135]

Multiple 6 with 3 and 1 with 2
2/18 = 19

7 0

3 years ago

What is the probability that a five-card poker hand contains the ace of hearts?

dusya [7]

What is the probability that a five-card poker hand contains the ace of hearts?
1/52

6 0

3 years ago

Which choice shows 8 less than f? A.8-f B.8/f C.f-8 D.8f

amid [387]

Answer: C

Step-by-step explanation: c is the correct answer. A is incorrect, because 8 is subtracting t, so it is a higher value. B is incorrect because it’s 8/f so 8 is greater. (If it was f/8 then 8 would be less). C is correct because 8 is being taken away from f, not the other way around. And lastly, d is incorrect bc there’s no way to tell which is greater/less. Hope this helped ;)

6 0

3 years ago

use the distributive property to multiply 924 x 5. multiply 5 by all the values 924 (900+20+4). Show the product

Levart [38]

The product is 4,620.

7 0

3 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

4 years ago

Read 2 more answers