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3 years ago

Find the solutions of the systems -6x-2y=8 and 7x-2y=-5

Mathematics

1 answer:

Daniel [21]3 years ago

7 0

Answer:

y=4

x= 3/7

Step-by-step explanation:

2y=8

Divide both sides by 2

2y÷2=8÷2

A.) y=4

Substitute 4 for y

7x−2y=−5

7x+(−2)(4)=−5

Simplify both sides of the equation.

7x−8=−5

Add 8 to both sides

7x−8+8=−5+8

7x=3

Divide both sides by 7

7x÷7= 3÷7

x= 3

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-8x+3=8x+27 I need help plz I’m trash at math

belka [17]

Answer:

-1.5

Step-by-step explanation:

See steps below:

-8x+3=8x+27

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3 years ago

X+2y=8 x-2y=-4 solve by system of equations

Vsevolod [243]

Answer:

Step-by-step explanation:

x + 2y = 8 -----------(I)

x - 2y = -4 -----------(II)

Add equation (I) & (II) and thus y will be eliminated and we can get the value of 'x'

(I) x + 2y = 8

(II) x - 2y = -4 {Now add}

2x = 4

x = 4/2

x = 2

Substitute x = 2 in equation (I)

2 + 2y = 8

2y = 8 - 2

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3 years ago

(9^(3))^(3) = 9 9 9 0 9 6 81

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Step-by-step explanation:

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3 years ago

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In the air, it had an average speed of 16 m/s In the water, it had an average speed of 3 m/s before hitting the seabed. The tota

julia-pushkina [17]

<h2>The stone fall in air for 7 seconds and fall in water for 5 seconds.</h2>

Step-by-step explanation:

Total distance to sea bed = 127 m

Let the distance traveled in air be s.

Distance traveled in water = 127 - s

Average velocity in air = 16 m/s

Average velocity in water = 3 m/s

Distance traveled in air = Average velocity in air x Time in air

s = 16 x t₁

$t_1=\frac{s}{16}$

Distance traveled in water = Average velocity in water x Time in water

127-s = 3 x t₂

$t_2=\frac{127-s}{3}$

We have total time is 12 seconds

That is

t₁ + t₂ = 12

$\frac{s}{16}+\frac{127-s}{3}=12\\\\3s+2032-16s=576\\\\13s=1456\\\\s=112m$

We have

s = 16 x t₁

112 = 16 x t₁

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7 + t₂ = 12

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3 years ago