Answer:
<u>Alternative hypothesis 1</u>: the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2</u>: the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
Recall that the null hypothesis is the fact you want to refute and is in doubt.
So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes.
</em>
The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:
<u>Alternative hypothesis 1:</u> the mean amperage at which the fuses burn out is > 40 amperes.
<u>Alternative hypothesis 2:</u> the mean amperage at which the fuses burn out is < 40 amperes.
Step-by-step explanation:
given,velocity = 5 m/s
and distance=12×1000=12000m
now,time =?
we have , v=s/t
or, t= s/v
so,t=12000/5
2400sec.....ans
=
2. Segment addition postulate
3. Substitution property of equality (AC=111; AB=7x+1; and BC=4x)
7. Symmetric Property of Equality
Answer:
see below
Step-by-step explanation:
We have to assume that the question is referring to the doubly-shaded length, the one that is 10 bright blue units long.
You can read the overall length of the shaded area as 5/4, from the markings.
For the next part, you need to count the number of units that are shaded bright blue (10) and the number that are shaded blue overall (15). As a fraction of those shaded blue overall, the ones shaded bright blue are 10/15 = 2/3.
So, the length shaded bright blue is 2/3 of the overall length of 5/4. It is represented by the product ...
Answer:
the answer is 2
Step-by-step explanation:
2×4=6
2×6=12
2×15=30
