Find the slope. aA. undefinedB.0
2 answers:
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Y = x² - 4x + 4
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
</span>
<span>
Answer: 4.47 units
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y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
</span>
<span>
Answer: 4.47 units
</span>
9514 1404 393
Answer:
- 40 ft
- t = 1 second
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
