The answer is <span>b. I and II
</span>
<span>Cost (NIS)
Jerusalem to Tel Aviv: J-TA = 269
Jerusalem to Holon: J-H = 201
Jerusalem to Ra’anana: J-R = 281
Tel Aviv to Jerusalem: TA-J = 235
Tel Aviv to Holon: TA-H = 263
Tel Aviv to Ra’anana: TA-R = 203
Holon to Jerusalem: H-J = 150
Holon to Tel Aviv: H-TA = 198
Holon to Ra’anana: H-R = 290
Ra’anana to Jerusalem: R-J = 176
Ra’anana to Tel Aviv: R-TA = 234
Ra’anana to Holon: R-H = 218
Options:
</span><span>I. Jerusalem - Tel Aviv - Ra’anana - Holon - Jerusalem
J-TA + TA-R + R-H + H-J = 269 + 203 + 218 + 150 = 840
840 < 900
II. Jerusalem - Holon - Tel Aviv - Ra’anana - Jerusalem
J-H + H-TA + TA-R + R-J = 201 + 198 + 203 + 176 = 778
778 < 900
III. Jerusalem - Ra’anana - Tel Aviv - Holon - Jerusalem
J-R + R-TA + TA-H + H-J = 281 + 234 + 263 + 150 = 928
928 > 900
Hence, options I and II are possible.</span>
That answer is 3y=x+1 I just used my graphing calculator
Answer:
53
Step-by-step explanation:
you just need to reflect your lines to find answer.
Answer:
4 and 6
Step-by-step explanation:
First, let's find all the pairs that add up to 10.
- 1 + 9, 2 + 8, 3 + 7, 4 + 6, and 5 + 5
Next, we find the difference between the addends for each pair.
- 9 - 1 = 8
- 8 - 2 = 6
- 7 - 3 = 4
- 6 - 4 = 2
- 5 - 5 = 0
As you can, see the numbers that add to 10 and have a different of 2 is 4 and 6.
Answer:
410 minutes
Step-by-step explanation:
Given that:
Time for which Jesse practices trumpet in the first week = 165 minutes
Time for which Jesse practices trumpet in the second week = 245 minutes
To find:
The total amount of time rounded to the nearest 10 minutes.
Solution:
To find the total amount of time for which Jesse practices, we need to add the time taken for practice in the first week and the time taken for practice in the second week.
Therefore, total time taken = 165 + 245 = <em>410 minutes</em>
It is already rounded off to the nearest 10 minutes.
Therefore, the answer is:
Total amount of time for which Jesse practices = 410 minutes