Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiply both sides by 100.
Divide both sides by 50.
The amount invested at 7% is .
The amount invested at 8% is
The amount invested at 9% is
Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.
Answer:
y = 12^8
Step-by-step explanation:
Log base 12, y^2 = 16
y2 = 12^16
y = sqrt ( 12^16) = (12^16)^1/2
y = 12^8
So convert to improper fracitons (improper=x/y where x>y and the current one is mixed where it is in t s/f form) so
40 and 4/5=(40 times 5)/5 and 4/5=200/5 and 4/5=204/5
50 and 7/8=(50 times 8)/8 and 7/8=400/8 and 7/8=407/8
area=legnth times width
legnth =407/8
width=204/5
multiply 407/8 and 204/5
407/8 times 204/5=(407 times 204)/(8 times 5)=83028/40=2075.7 square feet
the answer is 2075.7 ft^2 of seed
Answer:
D is the answers for the question
Step-by-step explanation:
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Answer: 0.4
Step-by-step explanation: