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Bad White [126]
3 years ago
6

How many inches are in 508 centimeters? 1 in. = 2. 54 cm Enter your answer in the box.

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

1,290.32

Step-by-step explanation:

508 x 2.54

Darina [25.2K]3 years ago
6 0

Answer:

200

Step-by-step explanation:

divide 508 by 2.54 and boom answer.

If you are confused on long division you can message me and I can try to help.

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What is 2/3 as a percent with one decimal place​
Doss [256]
2/3 is .666666 so that would be the percent
3 0
3 years ago
Which statement about the sum of the interior angle measures of a triangle in Euclidean and non Euclidean geometries are true
Sati [7]
Where are the statements?
7 0
3 years ago
Read 2 more answers
Help me do this please
Rom4ik [11]
Use the distributive property.
(3/8)*(16x-24)=(3/8)(16x)-(3/8)(24)
16x*3/8=48x/8=6x
24*3/8=72/8=9
6x+9

Hope this helps!
4 0
3 years ago
What is the value of x? How do you set up to solve?
nlexa [21]

Answer:

3x-22=80+x

3x-x=80+22

2x=102

x=51

Step-by-step explanation:

the exterior angle is (3x-22) and then is equal to sum of 80 and x

and then we get 51

6 0
2 years ago
Read 2 more answers
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
3 years ago
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