Which of the following expressions represents the product of 3 less that twice x and 2 more than the quantity of 3 times x

Givem the geometric sequence where à1=2 and the common ratio is 4, what is domain for N

The domain for N is All integers where n ≥ 1

Solution:

According to statement a1 = 2 and r = 4. This shows that r is greater than 1.

If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.

If starting value is 2, if we put n=0, then we get 2, but if we put a negative value than we would get a number which is not a part of our sequence.

Thus the domain of n is All integers where n greater than or equal to 1

3 0

4 years ago

Roland said it is possible to make a triangle from the following lengths: 31 inches, 70

dlinn [17]

Answer:

the teacher should be sad. the correct answer is 68 inches is NOT greater than 70 inches, therefore a triangle can't be created

Step-by-step explanation:

in a triangle, 2 sides added together have to be greater than the third side or else the triangle can't be created. therefore, since 31+37=68 inches, and 68<70, the triangle can't be created.

8 0

3 years ago

Find the value of x. A. X = 90 B. X = 32 C. X = 30 D. X = 15

Verizon [17]

A or d…………………………… ……

5 0

3 years ago

Read 2 more answers

A dog sits at a corner of a square with side length 44 meters. the dog runs 10 meters along a diagonal toward the opposite corne

wlad13 [49]

Refer to the figure given below while reading the solution.

Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.

And then position B when traveled 5 m towards the right turning 90°.

We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).

Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).

Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.