Assuming that the collision factor remains the same, by how much must an enzyme lower the activation energy of the reaction in o

Question

Gemiola [76]

2 years ago

14

Assuming that the collision factor remains the same, by how much must an enzyme lower the activation energy of the reaction in o

rder to achieve a 3×105-fold increase in the reaction rate?.

SAT

1 answer:

OlgaM077 [116] · Answer 1 · 2023-04-02T09:52:02+03:00

The activation energy must be lowered by 32490 kJ/mol.

<h3>What is activation energy?</h3>

The term activation energy refers to the energy that reactant particles must posses in order for their collision to result in chemical reaction.

Given that for the reactions;

k2/k1 = $3*10^5$

So;

$3*10^5$ = k2/k1 = E1/RT = E2/RT

Taking natural logarithm of both sides;

E2 - E1 = ln( $3*10^5$ ) × 8.314 × 310.15 = 32490 kJ/mol

Learn more about activation energy: brainly.com/question/11334504