What is the minimum value for the function shown in the graph? Enter your answer in the box. A sinusoid function graphed on a co
1 answer:
The sinusoidal function graph has a period of 2·π and a minimum point
with coordinates (-0.5·n·π, -6) where n = -5, -1, 3, ...
Response:
- The minimum value of the function is -6
The minimum value of a function is the lowest vertex value of the
function.
The given graph description, is the graph of the following function;
f(t) = 0.5·sin(t) - 5.5
The minimum value is given at the location where, sin(t) = -1, which gives;
f(t) = 0.5 × (-1) - 5.5 = -6
The minimum value of the function is therefore;
- f(t) =<u> -6</u>
Learn more about the graphs of functions here:
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The bases are both 2, so we would subtract the exponents. This is because the rule is
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as![\sqrt[4]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D)
(fourth root of 2)
(a^b)/(a^c) = a^(b-c)
In this case,
a = 2
b = 3/4
c = 1/2
So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4
After subtracting the exponents, the final exponent is 1/4
So the expression simplifies to 2^(1/4) which is the same as