Answer:
Tyler is correct. The temperature dropped at a rate of about 4° per hour between 4 and 6, while the temperature dropped at about 2.25° per hour between 6 and 10.
Edit: Explanation
The question is asking about which window of time had a <em>faster</em> decline in temperature, not a larger total change in temperature.
In a 2 hour timeframe, the temperature dropped 8°. (4-6 PM)
In a separate 4 hour timeframe, the temperature dropped 9°. (6-10 PM)
To find which window had a faster change in temp, I took the total temperature drop for each timeframe, then divided it by the number of hours each drop took.
8° / 2 = 4° per hour for 4-6 PM
9° / 4 = 2.25° per hour from 6-10 PM
Since the speed at which the temperature dropped per hour was greater from 4-6 PM than 6-10 PM, Tyler was correct.
Answer:
AAS
Step-by-step explanation:
Answer:
5.9..... there are a bunch of numbers after that but you would round it to 6.0
Step-by-step explanation:
3 and 5 eights. All you have to do is subtract 5- 11/8 which is 1 and 3/8 which will give you 3 and 5 over eight as a answere
Answer:
85/7
Step-by-step explanation:
log2 + log7(x-5) = 2
log(14(x-5)) = 2
14x - 70 = 10²
14x = 170
x = 170/14
x = 85/7 or 12 1/7
