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Tcecarenko [31]
3 years ago
11

Please help i will give brainiest to the correct answer!

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

1 by 1 by 1 1/3, 36, 12.

Step-by-step explanation:

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Find the volume of the largest circular cone that can<br> beinscribed in a shpere of radius 3.
Aleksandr [31]

Answer:

V =\dfrac{32}{3}\pi

Step-by-step explanation:

given,

radius of sphere = 3

volume of cone:

V = \dfrac{1}{3}\pi r^2h

r is the radius of circular base

h is the height of the cone

here r = x and h = 3 + y

now, volume in term of x and y

V = \dfrac{1}{3}\pi x^2(3+y)

Applying Pythagoras theorem

x² + y² = 3²

x = \sqrt{9-y^2}

V = \dfrac{1}{3}\pi ( \sqrt{9-y^2})^2(3+y)

V = \dfrac{1}{3}\pi ( 9-y^2)(3+y)

V = \dfrac{1}{3}\pi (27 + 9 y - 3 y^2-y^3)

differentiating both side

\dfrac{dV}{dy} =\dfrac{1}{3}\pi ( 9-6y- 3y^2)

for maxima  \dfrac{dV}{dy} = 0

\pi ( 3-2 y - y^2)=0

 y² + 2 y - 3 = 0

(y+3)(y-1)=0

 y = 1,-3

y cannot be negative so, volume at y = 1

V = \dfrac{1}{3}\pi (27 + 9 (1)- 3(1)^2-(1)^3)

V =\dfrac{32}{3}\pi

Hence, the largest cone which can be inscribed in the spheres of the radius 3 has volume  V =\dfrac{32}{3}\pi

5 0
3 years ago
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
lesya692 [45]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
                      Determining the amplitude, midline, and period 

The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
                            Determining the type of function to use 

Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x) = 1 sin ( \dfrac{1}{2}x)+5   <span>= Solution </span>
4 0
4 years ago
Pleaseee help mee <br> brainliest if right
Genrish500 [490]

Answer:

I would say 80 if not it's not -6

7 0
3 years ago
audrey has 32 dimes and quarters in her piggy bank with a total value of $6.50. how many of the coins are dimes and how many are
AfilCa [17]
22 quarters= $5.50
10 dimes= $1.00

$5.50 + $1.00 = $6.50
I just did trial and error. I started with 20 quarters and made changes until it worked.

4 0
3 years ago
Urgent!!
suter [353]

Answer:

$70.62

Step-by-step explanation:

110 x 0.6=66

66x0.07 + 66=$70.62

3 0
3 years ago
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