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3 years ago

What's the common denominator of 2/3 and 4/9

Mathematics

2 answers:

pshichka [43]3 years ago

8 0

Answer:

Um, no lo sé, lo siento, solo necesito los puntos

Step-by-step explanation:

Um, no lo sé, lo siento, solo necesito los puntos

Monica [59]3 years ago

6 0

Answer:

Step-by-step explanation:

common denominator of 2/3 and 4/9

9 is the answer

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Lucy bought 9 1/3 pounds of blueberries from the farmer's market and placed them in equal quantities in 7 bags. How many pounds

olga2289 [7]

Answer:

1 and 1/3

Step-by-step explanation:

9.334 divided by 7 equals 1.3334.

1.3334 simplifies into 1 and 1/3.

Hope this helps!

4 0

3 years ago

If x = 2 and y = 4, then (2x + 3y) ÷ 4 - 2 =

Xelga [282]

Answer:

Step-by-step explanation:

Remember to follow PEMDAS, the order of operation.

PEMDAS =

Parenthesis

Exponents (& roots)

Multiplications

Division

Addition

Subtraction

First, plug in 2 for x, and 4 for y

(2(2) + 3(4))/4 - 2

Simplify:

2 * 2 = 4

3 * 4 = 12

4 + 12 = 16

16/4 = 4

4 - 2 = 2

2 is your answer.

3 0

3 years ago

Read 2 more answers

Can some one tell me the answers for these I'm in a rush to my next class

Evgesh-ka [11]

1) 12 dollars
2) 8 games per month
3) 620 pencils total
4) 2 cantaloupes
5) 46 plums
6) 72 games in all
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8) 47 packs
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4 0

3 years ago

Among all right triangles whose hypotenuse has a length of 12 cm, what is the largest possible perimeter?

Veronika [31]

Answer:

Largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

Step-by-step explanation:

We are given the following information in the question:

Right triangles whose hypotenuse has a length of 12 cm.

Let x and y be the other two sides of the triangle.

Then, by Pythagoras theorem:

$x^2 + y^2 = (12)^2 = 144\\y^2 = 144-x^2\\y = \sqrt{144-x^2}$

Perimeter of Triangle = Side 1 + Side 2 + Hypotenuse.

$P(x) = x + \sqrt{144-x^2} + 12$

where P(x) is a function of the perimeter of the triangle.

First, we differentiate P(x) with respect to x, to get,

$\frac{d(P(x))}{dx} = \frac{d(x + \sqrt{144-x^2} + 12)}{dx} = 1-\displaystyle\frac{x}{\sqrt{144-x^2}}$

Equating the first derivative to zero, we get,

$\frac{dP(x))}{dx} = 0\\\\1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0$

Solving, we get,

$1-\displaystyle\frac{x}{\sqrt{144-x^2}} = 0\\\\x = \sqrt{144-x^2}}\\\\x^2 = 144-x^2\\\\x = \sqrt{72} = 6\sqrt{2}$

Again differentiation P(x), with respect to x, using the quotient rule of differentiation.

$\frac{d^2(P(x))}{dx^2} = \displaystyle\frac{-(144-x^2)^{\frac{3}{2}}-x^2}{(144-x)^{\frac{3}{2}}}$

At x = $6\sqrt{2}$ ,

$\frac{d^2(V(x))}{dx^2} < 0$

Then, by double derivative test, the maxima occurs at x = $6\sqrt{2}$

Thus, maxima occurs at x = $6\sqrt{2}$ for P(x).

Thus, largest perimeter of the triangle =

$P(6\sqrt{2}) = 6\sqrt{2} + \sqrt{144-72} + 12 = 12\sqrt{2} + 12 = 12(\sqrt2 + 1)$

7 0

3 years ago

Under her cell phone plan, Rajani pays a flat cost of $65 per month and $5

riadik2000 [5.3K]

If she wants to only use 85 a month then doing the math it would be 85-65=20 divided by 5 equals 4 so she would get 4 gigabytes while staying within her budget :)

Brainiest please

3 0

3 years ago