Answer:
The general equation following the pattern becomes is 7 + (n - 1)×2
Where, n = The figure number - 1
Step-by-step explanation:
The pattern in the question can be described as follows;
Figure 2 = (5 + 2) squares boxes = 7 squares boxes
Figure 3 = (5 + 2 + 2) squares boxes
Figure 4 = (5 + 2 + 2 + 2) squares boxes
Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;
7 + (n - 1)×2.
Answer:
The correct option is, Exponential Decay, $23,914.85.
Step-by-step explanation:
A farmer buys a tractor for $50,000.
It is provided that the the tractor depreciates 10% per year.
The exponential function for decay is:
Here,
a = initial value
r = decay rate
t = time
Compute the value of the tractor in 7 years as follows:
Thus, the correct option is, Exponential Decay, $23,914.85.
Answer:
y = 1.6x
Step-by-step explanation:
y is the total amount/pounds of almonds that Lark bought. x is the amount that Tessa bought. 3/5 is the same as 0.6. If we multiplied Tessa's amount by 0.6 it would decrease by 2/5 so we have to add 1 to make it 1.6. To find how much Lark bought multiply 1.6 and Tessa's amount.
The answer is: Yes, all conditions for inference are met.
For each deposit she makes 3.5 is being subtracted for the money she makes so 8000 would be 45 tries
