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2 years ago

There is a bag filled with 6 blue and 5 red marbles.

Mathematics

2 answers:

laiz [17]2 years ago

3 0

Answer:

25/121

Step-by-step explanation:

This is called sampling with replacement.

The probability of getting a red marble in one sample is 5/11. Since you are sampling twice, the probability of picking a red marble both times is 5/11 X 5/11 = 25/121. That is slightly less than ⅕.

Nuetrik [128]2 years ago

3 0

Answer: 61/121

=============================================

Work Shown:

B = event of getting a blue marble

R = event of getting a red marble

P(B) = (6 blue)/(6+5 total) = 6/11

P(R) = (5 red)/(11 total) = 5/11

P(2 blue) = P(B)*P(B) = (6/11)*(6/11) = 36/121

P(2 red) = P(R)*P(R) = (5/11)*(5/11) = 25/121

---------

P(2 same color) = P(2 blue OR 2 red)

P(2 same color) = P(2 blue) + P(2 red)

P(2 same color) = 36/121 + 25/121

P(2 same color) = (36+25)/121

P(2 same color) = 61/121

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The angles of elevation and depression are formed by the line of sight and the horizontal line. When the line of vision is above the horizontal line, the angle is of elevation, and if the line of sight is below the horizontal, the angle is of depression.

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In the diagram you can notice that both angles, of elevation and depression, have the same value.

Then, the answer is: The angle of depresion from the top of the taller building and the angle of elevation from the top of the shorter building are alternate interior angles.

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3 years ago

A drawer contains 4 orange colored pencils and

sergij07 [2.7K]

Answer:

4/9 or four out of nine

Step-by-step explanation:

There are nine pencils total, and 4 of them are orange

6 0

2 years ago

Please solve the following question!!

Komok [63]

2(21x − 7) + 4(3x + 2) = 6(2x + 9) + 3
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4 0

3 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

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3 years ago

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astraxan [27]

Answer: The answer is A

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3 years ago