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nexus9112 [7]
3 years ago
8

The graph below shows the solution to which system of inequalities? ​

Mathematics
1 answer:
solong [7]3 years ago
6 0

Answer:

C

Step-by-step explanation:

The graph shows it clearly.

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When comparing the ratio 9^2 to 9^7 luciano calculated 1/9^5 is luciano correct and why or why not
Leto [7]

Answer:

yes

Step-by-step explanation:

using the rule of exponents

\frac{a^{m} }{a^{n} } = \frac{1}{a^{(n-m)} } , then

\frac{9^2}{9^{7} } = \frac{1}{9^{(7-2)} } = \frac{1}{9^{5} }

3 0
2 years ago
Write an equation of a circle whose center is (-3,2) and whose diameter is 10
gayaneshka [121]
The formula for a circle with center (h,k) and radius (r) is as follows:

(x – h)² + (y – k)² = r²

If the diameter of the circle is 10, we know that the radius of the circle must be equal to 5. Insert any known equations into the formula above:

(x – (-3))² + (y – 2)² = 5²

Simplify both sides of the equation:

(x + 3)² + (y – 2)² = 25

This is the equation of a circle with the given measurements.

I hope this helps!
5 0
3 years ago
Which statement is true about a negative number and its additive inverse?
MakcuM [25]

Answer:

B.) They are on opposite sides of zero on the number line.

stay safe and have a great day!

6 0
3 years ago
Read 2 more answers
The quadratic regression graphed on the coordinate grid represents the height of a road surface x meters from the center of the
Viktor [21]

Answer:

The height of the surface increases, then decreases, from the center out to the sides of the road.

Step-by-step explanation:

Let

y------> the height of the surface

x------> the road

we know that

The quadratic regression graphed represent a vertical parabola open downward

The function increase in the interval -------->   [-5,0)      

The function decrease in the interval -------->   (0,5]

therefore

The height of the surface increases, then decreases, from the center out to the sides of the road.

3 0
3 years ago
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Lets be frineds :))))
tatiyna

Answer:

thanks :)

Step-by-step explanation:

7 0
3 years ago
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