Question

Let x be a positive number such that = 4x + 9" alt="2x^2 = 4x + 9" align="absmiddle" class="latex-formula">. If x can be written in simplified form as $\dfrac{a + \sqrt{b}}{c}$ such that a, b, and c are positive integers, what is a + b + c?

Answer 1

Answer:

(4 ± 2$\sqrt{22}$) ÷ 4

Step-by-step explanation:

i changed equation to be 2x² - 4x - 9 = 0

i used the quadratic formula:  (-b ± $\sqrt{b^2-4ac}$) ÷ 2a

where:

a = 2

b = -4

c = -9