Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
I think it would be B. The average monthly sales for the big toy company because its giving data over history
Answer:
Time taken to travel from one track to the next = 0.08ms
Initial track= 15 0
4 (15-4)*(0.08)= 0.88
40 (40-4)*(0.08)= 2.88
35 (40-35)*(0.08)= 0.4
11 (35-11)*(0.08)= 1.92
14 (14-11)*(0.08)= 0.24
7 (14-7)*(0.08)= 0.56
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Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms
Explanation:
We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.
