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Lesechka [4]
2 years ago
7

In AWXY, mW Find mZX (2x – 12), m_X = (2x + 17), and m_Y = (9x-7) Find m

Mathematics
1 answer:
sladkih [1.3K]2 years ago
5 0

Answer:

45

Step-by-step explanation:

The sum of interior angles in a triangle is equal to 180

2x - 12 + 2x + 17 + 9x - 7 = 180 add like terms

13x - 2 = 180 add 2 to both sides

13x = 182 divide both side by 13

x = 14

m<X = 2x + 17 replace x with 14

2*14 + 17 = 45

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Mashutka [201]
The angle of elevation from the hiker to the park ranger is the same as the angle of depression from the ranger to the hiker, 29°.

The tangent function of an angle is the ratio of the opposite side (500') to the adjacent side (x) in the right triangle shown. That is
   tan(29°) = 500' / x

Multiplying the equation by x/tan(29°) gives
   x = 500' / tan(29°)
   x ≈ 500' / 0.5543
   x ≈ 902 ft
6 0
3 years ago
Evan is thinking of a number that contains the digit 2. The digit 2 in Evan's number has 10 times the value of the digit 2 in th
Len [333]

Answer:

200,000

Step-by-step explanation:

The number Evan could be thinking about is 200,000. I got this number because the value of the digit 2 in the number 328,907 is 20,000. Also, the number Evan is thinking about is 10 times the value of 20,000. So, I did 20,000 times 10 and got 200,000.

8 0
3 years ago
Which expression is equivalent to 9p-3p +2
Dafna1 [17]
You have the right answer 6p+2
5 0
3 years ago
What does it mean if y is inversely proportional to x squared
Andrews [41]

Answer:

the answer of this question is

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5 0
3 years ago
Read 2 more answers
7.7.33
GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
7 0
3 years ago
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