Rosa brought d drawings to an art show. After selling 15 of them, she had 38

Can anyone Help I have 25 questions, 2hr 40mins remaining,

11Alexandr11 [23.1K]

Combining the like-terms, the result of the addition of polynomials f(x) and g(x) is given by:

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

<h3>How do we add polynomials?</h3>

We add polynomials combining the like-terms, that is, adding terms with the same exponent.

In this problem, the polynomials are:

$f(x) = 3x^{\frac{1}{2}} + 7x^{-\frac{1}{4}} + 8x^{-4}$

$g(x) = -\frac{7}{4}x^{\frac{1}{2}} + 12x^{-\frac{1}{4}} - 21x^3$

Combining the like terms, the addition is given by:

$f(x) + g(x) = \left(3 - \frac{7}{4}\right)x^{\frac{1}{2}} + (7 + 12)x^{-\frac{1}{4}} + 8x^{-4} + 21x^3$

$f(x) + g(x) = 21x^3 + \frac{5}{4}x^{\frac{1}{2}} + 19x^{-\frac{1}{4}} + 8x^{-4}$

More can be learned about addition of polynomials at brainly.com/question/9438778

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8 0

1 year ago

Factor the trinomial x^2 - 3x - 40

Elenna [48]

The answer is (x+5)(x-8)
Hope this helps

8 0

3 years ago

Read 2 more answers

SHOW YOUR WORK. Algebra question. 100 POINTS. Easy

matrenka [14]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which

kifflom [539]

The quadrant that the graph will not go through is the second quadrant.

The reason is that the slope is positive and there was a translation 6 units down

<h3>How to know the quadrant the graph will not pass</h3>

The quadrants are named in anticlockwise direction starting from the first which has x - positive and y - positive

The graph of y = 2x/3 is a graph with positive slope, moving through the third and first quadrant.

y = 2x/3 - 6 means a translation 6 units down and this pushed the line to get to the fourth quadrant

Hence the remaining quadrant that is untouched is the second quadrant

The graph is attached

learn more about graphs here:

brainly.com/question/25184007

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8 0

1 year ago

Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

denis23 [38]

Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

$P(a\ \textless \ X\ \textless \ b)=P\left(z\ \textless \ \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\ \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \ \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \ \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\ \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344$ </span>

6 0

3 years ago