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Nookie1986 [14]
2 years ago
7

Simplify (3x^2-y)^2. please

Mathematics
1 answer:
In-s [12.5K]2 years ago
8 0
9x^4+y^2-6yx^2
Hope it helped
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Deborah has two paintings in her portfolio and paints three more each week.Kai has twelve paintings in her portfolio and paints
elena-14-01-66 [18.8K]
Well, we can set up these equations like this-
Deborah- 2+3w
Kai- 12+2w
w=number of weeks that pass
Now, we set them equal to each other:
2+3w=12+2w

Solve for w
2-12=2w-3w
-10 = -1w
w = 10
10 weeks. Hope this helped!
4 0
3 years ago
Tricia got a 6% raise on her weekly salary. The raise was $30 per week. What was her original weekly salary in dollars per week?
serious [3.7K]

Answer:   Original salary = $500  

Step-by-step explanation:  Tricia got a 6% raise on her weekly salary. The

raise was $30 per week.  

Let x be the original salary  

x times the raise percentage = raise amount  

6%= 6/100=0.06, raise amount = 30    

Now we solve for x  

Divide by 0.06 on both sides    

Original salary = $500

6 0
3 years ago
How can you tell when a pattern shows counting on by tens?
velikii [3]
<span><u><em>Answer:</em></u>
The difference between successive terms is 10

<u><em>Explanation:</em></u>
To know the factor by which a certain pattern is increasing/decreasing, you need to subtract its successive terms.

If the subtraction gives you 10, this means that the pattern is increasing by 10

<u>Examples:</u>
<u>10, 20, 30, 40, 50, .....</u>
20 - 10 = 10
30 - 20 = 10
40 - 30 = 10
50 - 40 = 10
The difference between each two successive terms is 10. This means that each time we add 10 to the number we have in order to get the next one.
Therefore, this pattern is increasing by 10

<u>37, 47, 57 , .....</u>
47 - 37 = 10
57 - 47 = 10
The difference between each two successive terms is 10. This means that each time we add 10 to the number we have in order to get the next one.
Therefore, the pattern is increasing by 10

Hope this helps :)</span>
7 0
3 years ago
What is a function exponential
valkas [14]
(Credit goes to google)<span>f ( x ) = a </span>x<span>. where x is a variable, and a is a constant called the base of the </span>function<span>. The most commonly encountered </span>exponential-function<span> base is the transcendental number e , which is equal to approximately 2.71828.</span>
3 0
3 years ago
Read 2 more answers
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
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