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Lelu [443]
4 years ago
13

Part A: Solve −np − 70 < 40 for n. Show your work. (4 points) Part B: Solve 4w − 7k = 28 for k. Show your work.

Mathematics
1 answer:
kondaur [170]4 years ago
4 0
Hey!

For part A, let's write the problem,
-np-70\ \textless \ 40
Add 70 to both sides...
-np-70+70\ \textless \ 40+70
-np\ \textless \ 110
We are going to reverse the inequality, to do this we are going to multiply both sides by -1.
\left(-np\right)\left(-1\right)\ \textgreater \ 110\left(-1\right)
pn\ \textgreater \ -110
Divide both sides by p.
\frac{pn}{p}\ \textgreater \ \frac{-110}{p}
Our answer would be,
n\ \textgreater \ -\frac{110}{p}

Let's go with Part B. Let's write the problem,
4w-7k=28
Subtract 4w from both sides,
4w-7k-4w=28-4w
-7k=28-4w
Divide both sides by -7.
\frac{-7k}{-7}=\frac{28}{-7}-\frac{4w}{-7}
If we simplified it, we would be left with,
k=-\frac{28-4w}{7}

Thanks!
-TetraFish

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Step-by-step explanation:

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<h3>20 subtracted from three times a number is 6 more than the number. Then the number is 13</h3>

<em><u>Solution:</u></em>

<em><u>Given statement is:</u></em>

20 subtracted from three times a number is 6 more than the number

We can translate the sentence into algebraic expression

Let "a" be the unknown number

Then,

20 subtracted from three times "a" is 6 more than "a"

Which means,

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Source for quote:

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