Question

Luke throws a fair coin n times

Answer 1

Answer:

$\frac{n^{2} }{4}$

Step-by-step explanation:

We know that the coin has 2 sides, which is tails and heads.

the total number of options is 2. whereas if tails or heads, 1 options

For tails:

$(\frac{1}{2}) *n$

$\frac{n}{2}$

For heads:

$(\frac{1}{2} ) * n$

$\frac{n}{2}$

If he does this in a row and expects 1 head and tail:

$\frac{n}{2} * \frac{n}{2}$

$\frac{n^{2} }{4}$