Prompt - Select an image of an art work from smarthistory by looking at the "Histories of Art" tab.
Objective - This is an exercise to get comfortable with applying the language of art as well as the steps of the Art Analysis ChartActions (summarized below).
You must include in this exercise four short, clearly separated paragraphs (2-3 sentences) consisting of the concerns printed in bold:
1. description of the chosen image (include the image information: title, artist's name, year, medium, etc.) and say what you see.
2. analysis of what you see by saying what each element is achieving (e.g. "converging lines are used to draw our attention to the focal point.")
3. interpretation of the image by saying what the work is about and what it means.
4. evaluation of the image by talking about where you think the "value" lies in your chosen image, and explain why. The term value here is not in the context of light or dark as in formal attributes. It refers to what is significant in the work of art you are analyzing, and how successful or unsuccessful it has been executed. Evaluation here is an exercise in reasoning/arguing based on your previous three paragraphs.
The inside angles of the triangle add to equal 180 and so does m/FEG with unknown triangle angle.
x+2x = x+40
2x = 40
x = 20
mFEG
= 20 + 40
= 60
answer C
Answer:
Step-by-step explanation:
The equation being shown in the question is the absolute value of x. Absolute values when graphed show up as a V-shaped graph pointing upwards. This is because whatever value is passed as an input will output a positive, regardless of whether the input is positive or negative. Meaning that both 4 and -4 will output 4. That is why the graph is a V-shaped because the outputs repeat for both positive and negative inputs. In this case since the negative is outside the absolute value brackets the positive value given from the absolute value of the input will be turned into a negative. So this will cause the V-shape graph to be reflected across the x-axis. As seen in the attached picture below.
1)
2x^2 - 13x - 24 = 0;
the discriminant is : ( - 13 )^2 - 4 * 2 * ( -24 ) = 169 + 192 = 361 = 19^2 => we have two different rational-number solutions ;
2)
[ -2( x + 2 ) - 3( x - 5 ) ] / [ ( x - 5 )( x + 2 ) ] < 0 <=>
( -5x + 11 ) / [ ( x - 5 )( x + 2 ) ] < 0
We have 2 situations :
a) - 5x + 11 < 0 and ( x - 5 )( x + 2 ) > 0 => x∈ ( 11 / 5 , + oo ) and x∈( -oo, - 2 )U
( 5 , + oo ) => x∈( 5, +oo);
b) - 5x + 11 > 0 and ( x - 5 )( x + 2 ) < 0 => x∈(-oo, 11/5) and x∈( -2, 5 ) =>
x∈( -2, 11/5 );
Finally, x∈ U (-2, 11 / 5 ) U ( 5, +oo).
