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3 years ago

What is the 22nd term of the arithmetic series where a1=8 and a9=56?

1 answer:

7 0

A 1 = 8, a 9 = 56
a 9 = a 1 + 8 d
56 = 8 + 8 d
8 d = 48
d = 6 ( common difference )
a 22 = a 1 + 21 d = 8 + 21 · 6 = 8 + 126 = 134

SO the answer is the 22nd term is 134

I really hope this helps!

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ValentinkaMS [17]

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