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Pepsi [2]
3 years ago
6

What is the 22nd term of the arithmetic series where a1=8 and a9=56?

Mathematics
1 answer:
Wewaii [24]3 years ago
7 0
A 1 = 8, a 9 = 56
a 9 = a 1 + 8 d
56 = 8 + 8 d
8 d = 48
d = 6  ( common difference )
a 22 = a 1 + 21 d = 8 + 21 · 6 = 8 + 126 = 134


SO the answer is the 22nd term is 134

I really hope this helps!
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