Question

What is the 22nd term of the arithmetic series where a1=8 and a9=56?

Answer 1

A 1 = 8, a 9 = 56
a 9 = a 1 + 8 d
56 = 8 + 8 d
8 d = 48
d = 6  ( common difference )
a 22 = a 1 + 21 d = 8 + 21 · 6 = 8 + 126 = 134


SO the answer is the 22nd term is 134

I really hope this helps!