(3x^4)^2 = (3^2)*(x^4)^2 = 9*(x^(4*2)) = 9*x^8 . . . . . the 3rd selection
The z-score corresponding to a cumulative area of 1 - 0.0122 = 0.9878 is 2.25.
Therefore the z-score corresponding to a cumulative area of 0.0122 is the negative of 2.25 = -2.25.
Y=Acos(p)+m, A=amplitude, p=period, m=midline, in this case:
A=1/2, p=360(t/12)=30t, m=(10-9)/2+9=9.5 so
h(t)=(1/2)cos(30t)+9.5
Answer:
try right 3, up 4. if not, try right 4, up 3.