Answer:
a(10) = 3^9 = 19683
Step-by-step explanation:
In this sequence each new term is equal to 3 times the previous term. Thus, 3 is the common ratio. The first term is 1.
The general formula for the nth term of a geometric sequence i
a(n) = a(1)*r^(n -1), where r is the common ratio.
Here, a(n) = 1*3^(n - 1), and so
the 10th term is
a(10) = 1*3^(10 - 1), or
a(10) = 3^9 = 19683
Answer:
{r:r<17}
Step-by-step explanation:
<em>giv</em><em>en</em><em> </em><em>r+10<-3(2r-3)+6(r+3)</em>
change the < to = to solve the equation
thus, r+10=-3( 2r-3 )+6( r+3 )
r+10= -6r +9 +6r +18
r+10= 9+18
r+10=27
r=27-10
r=17
Answer:
No
Step-by-step explanation:
Lets simplify both expressions:
We will start with Gloria's first expression:
Apply distributive property:
Combine like terms, we are then left with:
Now lets simplify the second expression
Apply distributive property
Rearrange:
Now we can see that the two equations are not equal, as the first is 12 greater than the second. Another way we could have tested this was plugging in a value for x and then solving.
Nate's package is 8 kilograms. This is because, if there are 1,000 grams in 1 kilogram, 8,000/ 1,000= 8 Therefore, the mass of his package is 8 kilograms.
Have a Merry Christmas!