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3 years ago

Which of the following is the graph of (see images)

Mathematics

1 answer:

Liula [17]3 years ago

6 0

Answer:

The first Graph

Step-by-step explanation:

its not the third because it's a dotted line, so it wouldn't be equal to. it's not the second because it's shaded in the wrong place, making it less than.

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Help me on this question. would be nice if you could also graph it as well

Gre4nikov [31]

Bro it definitely A I’m
Telling you

6 0

2 years ago

Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].

Vilka [71]

The average value is given by

$\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt$

Setting $y=\cos5t$ , you get $\mathrm dy=-5\sin5t\,\mathrm dt$ , and the integral becomes

$\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy$
$=-\dfrac1{30}\dfrac{y^{14}}{14}\bigg|_{y=\cos20}^{y=\cos50}$
$=-\dfrac{\cos^{14}50-\cos^{14}20}{420}\approx-0.00145$

6 0

3 years ago

Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a

Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio ) her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , $1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2}$ .

Also , simplifying her rate , $6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4}$ .

Now , ratio of his work by challenge is :

$R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}$

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0

3 years ago

Read 2 more answers

In the year 1987, an investment was worth $29,800. In the year 1997, this

Veseljchak [2.6K]

Answer:

a) 46.98%

b) increasing rate of change

Step-by-step explanation:

In year 1987, investment worth $29800

In year 1997, investment worth $43800

Rate of change = 1997investment - 1987investment / 1987investment × 100

Rate of change = 43800 - 29800/29800 × 100

= 14000/29800 × 100

= 0.46979 × 100

= 46.98%

Therefore, the rate of change of the investment during the time period is 46.98%.

b) The rate of change of the investment is increasing. This is as a result of the following reasons. First, the value of rate of change is positive. Second, there is no value for rate of change for period before the time period so we cannot compare rate of change.

8 0

3 years ago

Please help with this Khan Question :)

astraxan [27]

Answer:

the answer is A

Step-by-step explanation:

4 0

2 years ago