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Lapatulllka [165]
3 years ago
6

Help I don't really get this!

Mathematics
1 answer:
Fantom [35]3 years ago
6 0

Answer:

ask your teacher about this wag puro asasa sa iba Kaya ka pinag aaral para matutu ka right

Step-by-step explanation:

yes

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If you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?
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What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29

5 0
3 years ago
Read 2 more answers
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Answer:

I think the answer is 8

Step-by-step explanation:

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