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jasenka [17]
3 years ago
12

What is the distance between a line that has endpoints at (1,5) and (1,-5)?

Mathematics
1 answer:
Tanzania [10]3 years ago
5 0
Since the x values (1) and (1) are the same, we just have to worry about the (5) and (-5)

the distance between a (5) and (-5)
would be  (5) - (-5)
which is equal to   (5) + (5) = 10

therefore your answer would be C. 10

note that distance should always be a positive number
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Mathematical question, please see the picture. Thanks
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Answer:

B) $23.45

C) $157.50

A + B + C = $330.95

Step-by-step explanation:

$6.70 × 20 = $137 17.5% of $137 = $23.45

45c × 350 = $157.5

$150 + $23.45 + $157.50 = 330.95

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Determine the truth value of the following given that the statement p is true and the statement q is false. (~p) ∨ q
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How do i solve literal equations? ex. p=2(a b) solve for b
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3 years ago
How can you determine if a triangle on the coordinate plane is a rigjt triangle?
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Help I'm taking a k12 quiz 2.04: composite figures but, I can't figure these out can anyone help me?
ICE Princess25 [194]
All of these can be solved by separating complex figur into simpler one.
Needed formulas are:
Area of rectangle A=a*b
Area of triangle A=a*h/2
Area of paralelogram A= a*h

QUESTION 1.
When we connect points F and S we get a rectangle and a triangle.
Dimensions of sides of a rectangle are a=9 and b=2. 
A=9*2=18 units^{2}
For a triangle we need to take one side and it's height. Let's take side FS because it's easiest to find the height.
a=9
h=6
A=9*6/2=27units^{2}

Tot+al area of a figure: 
A=18+27=45units^{2}

QUESTION 2.
We connect point (1,1) with (1,-2) and (-6,1). This way we get a rectangle and three triangles.
Rectangle:
a=3
b=4
A=3*4=12units^{2}

Top right triangle:
a=4
h=3
A=4*3/2=6units^{2}

Top left triangle:
a=7
h=2
A=7*2/2=7units^{2}

Bottom left triangle:
a=7
h=3
A=7*3/2=10.5units^{2}

Total area of a figure:
A=12+6+7+10.5=35.5units^{2}

QUESTION 3.
We connect points (-4,2) and (-1,3). This way we get a paralelogram and a rectangle.

Paralelogram:
a=6
h=1
A=6*1=6units^{2}

Rectangle:
a=distance between (-4,2) and (-1,3) = \sqrt{ (-1-(-4))^{2} + (3-2)^{2} } = \sqrt{10}
b = distance between (-4,2) and (-2,-4) = \sqrt{ (-2-(-4))^{2} + (-2-2)^{2} } = \sqrt{20}
A=a*b=\sqrt{10} * \sqrt{20} = \sqrt{200} =10 \sqrt{2}units^{2}

Paralelogram:
a=6
h=1
A=6*1=6units^{2}

Total area of a figure:
A=10 \sqrt{2} + 6 units^{2}

QUESTION 4.
We coonect missing side of a triangle. That side has a length of: 6in-3in=3in. Vertical side of triangle is: 13in-7in=6in
Area:
a=3
h=6
A=3*6/2=9in^{2}

Rectangle:
a=7in
b=6in
A=7*6=42in^{2}

Total area of a figure:
A=9+42=51in^{2}
7 0
3 years ago
Read 2 more answers
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