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kompoz [17]
3 years ago
11

You purchase a new stereo for $500 it will decrease in value by 16% each year. How would I write this at an exponential equation

Mathematics
1 answer:
ozzi3 years ago
8 0

Answer:

500=-16x

Step-by-step explanation:

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5 divides by 1/2 is 10. 10 1/2 meter pieces
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3 years ago
Write the integer that represents the situation. °F represents the change The temperature was 15°F. It dropped so that the tempe
Simora [160]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

-15

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

  • The temperature dropped from 15°F to 0°F.
  • The change was negative in value since it dropped to a lower temperature.
  • The temperature dropped by 15 degrees, so we would fill in the blank with -15.

⸻⸻⸻⸻

»»————- ★ ————-««  

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3 0
3 years ago
Last month, you were able to purchase 8 computers. By the middle of the current month, you were able to purchase 8 more computer
Arada [10]

Answer:

125 %

Step-by-step explanation:

Computers purchased in the last month = 8

By the middle of the current month, 8 more computers than the last month were purchased. This means, total number of computers purchased by middle of current month = 8 + 8 = 16

Number of computers purchased by end of current month = 2

So,

Total computers purchased by current month = 16 + 2 = 18

We have to find the percentage increase in the number of computers from last month's purchases to the end of this month's purchases. The formula for percentage change is:

\text{Percentage Change}=\frac{\text{New Value - Original Value}}{\text{Original Value}} \times 100\%

Here, Original Value is the number of computers from last month and New Value is the number of computers from current month. Using the values in the formula, we get:

\text{Percentage Change}=\frac{18-8}{8} \times 100\% = 125\%

Thus, there was a 125% increase from last month's purchases to the end of this month's purchases

7 0
4 years ago
What percentage of a radioactive species would be found as daughter material after five half-lives?
dalvyx [7]
The answer is 3.125%.

The relation between number of half-lives (n) and amount of sample that remained (x) can be expressed as:
(1/2)^{n} =x

It is given:
n = 5

To find x, we will change n in the equation with five:

<span>(1/2)^{n} =x
</span>⇒ <span>(1/2)^{5} =x
</span>⇒ <span>0.5^{5} =x
</span>⇒ x=0.03125 =  \frac{3.125}{100} = 3.125%

Therefore, 3.125% of a radioactive species <span>would be found as daughter material after five half-lives.</span>
3 0
3 years ago
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