Answer:
59049 digits
Step-by-step explanation:
Given
Digits = 0 to 9
Required
Determine number of 5 digit pins that must not contain 0
There are 10 digits.
Since the pin must not contain 0, there are 9 digits left to select from.
The question didn't state that a digit can not be repeated, so I'll assume that repetition of digit is allowed.
The 1st digit of the 5 could be any of the 9 digits
The 2nd could be any of the 9 digits
The 3rd could be any of the 9 digits
The 4th could be any of the 9 digits
The 5th could be any of the 9 digits
Hence, number of selection is calculated as this:
Selection = 9 * 9 * 9 * 9 * 9
Selection = 59049
Answer:
19 shows direct variation
20 does not (guessing for this one a bit)
19- Shows a steady increase of four in y for each one in x
20- Shows no increase
Step-by-step explanation:
19 is a constant increase by 4, 20 does not show either
Answer:
<em>ab+bc+ca=0</em>
Step-by-step explanation:
We are given:
xyz=1
Separating equations:
Solving the first equation for x:
Solving the second equation for y:
Substituting in
xyz=1:
Adding the exponents:
Since 
:
The base is z on both sides so we get rid of them:
Multiplying by ab:
bc+ac+ab=0
Reordering:
ab+bc+ca=0
E=number of eight cent stamps
t=number of ten cent stamps bought
w=number of 2 cent stamps bought
number of eight=number of ten
e=t
as many 2 cent as the other 2 combined
e+t=w or
2e=w=2t
total she bouthgt 4.40
4.40=440 cents
8e+10t+2w=440
solve for t or e, I solve for t
8t+10t+2(2t)=440
18t+4t=440
22t=440
divide 22
t=20
t=e
20=e
w=2e
w=2(20)
w=40
answer is
20 eight cent
20 ten cent
40 two cent
