Answer:
-4 11/16
Step-by-step explanation:
The answer is 200 pounds
Let x be the number of pounds of the second chocolate that should be added
First chocolate: 300 pounds
cocoa to caramel = 1 to 7
So, there are in total 8 parts (1 + 7 = 8)
There is:
Cocoa: 1/8 * 300 pounds
Caramel: 7/8 * 300 pounds
Second chocolate: x pounds
cocoa to caramel = 1 to 15
So, there are in total 16 parts (1 + 15 = 16)
There is:
Cocoa: 1/16 * x pounds
Caramel: 15/16 * x pounds
Resulting chocolate: 300 + x pounds
cocoa to caramel = 1 to 9
So, there are in total 10 parts (1 + 9 = 10)
There is:
Cocoa: 1/10 * (300 + x) pounds
Caramel: 9/10 * (300 + x) pounds
Since in all chocolate, there is only one part of cocoa, it is easy to add up the amounts of cocoa:
1/8 * 300 + 1/16 * x = 1/10 * (300 + x)
300/8 + x/16 = 300/10 + x/10
75/2 + x/16 = 30 + x/10
75/2 - 30 = x/10 - x/16
75/2 - 60/2 = 8x/80 - 5x/80
(75 - 60)/2 = (8x - 5x)/80
15/2 = 3x/80
80 * 15/2 = 3x
40 * 15 = 3x
600 = 3x
x = 600/3
x = 200 pounds
Answer:
5
out of
5
(
2
)
+
5
(
−
5
t
)
.
5
(
2
−
5
t
)
Step-by-step explanation:
Answer:
Step-by-step explanation:
The formula of an area of a rectangle:
b - base
h - height
We have A = 144x ft² and h = 8. Substitute and solve for b:
<em>divide both sides by 8</em>
The formula of a perimeter of a rectangle:
Substitute:
The price of the fries would be $2.50, the price of the drink would be $2.50, and the price of the cheeseburger wold be $7.50.
We can write a set of equations to represent the prices, if 'f' is fries, 'd' is drink, and 'c' is cheeseburger:
c = 3f
f = d
Using these equations, we can then write out the sum of the items also, as it would be c + f + d = 12.50, but as we know that c = 3f and d = f, we can write it as 3f + f + f = 12.50, and then solve:
3f + f + f = 12.50
5f = 12.50
÷ 5
f = $2.50
Now that we know the price of the fries, we know that the price of the drink is the same, so the drink is also $2.50. Then, we can multiply 2.50 by 3 as we know that the cheeseburger is 3 times the cost of the fries, and 2.50 × 3 = 7.50.
I hope this helps!