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AleksAgata [21]
3 years ago
13

Find the missing value so that the two points have a slope of -13/2 (-2,y) and (0,-4)

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0

Solution:

<u>Note that:</u>

  • Given points = (-2,y) and (0,-4)
  • Slope = -13/2
  • Formula: y₂ - y₁/x₂ - x₁

<u>Forming an equation:</u>

  • y₂ - y₁/x₂ - x₁ = Slope
  • => -4 - y/0 - (-2) = -13/2

<u>Solving the equation:</u>

  • => -4 - y/0 + 2 = -13/2
  • => -4 - y/2 = -13/2
  • => -4 - y = -13
  • => -y = -13 + 4
  • => -y = -9
  • => y = 9

The missing value is 9.

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Find and interpret the slope of the line containing the given points. (12,4) and (10,10)
MAVERICK [17]

Answer:

3/-1

Step-by-step explanation:

The slope is 3/-1 (Rise 3 on the y axis, run to the negatives by 1 on the x axis)

To find the slope of two points, use the formula of y2-y1/x2-x1 (For example, with this equation it would be 10-4/10-12)

I'm not sure what it means to interpret the slope, but hopefully this helped you!

3 0
3 years ago
If x is the number of odd integers between 10
Anastasy [175]

Answer:

C. 41

Step-by-step explanation:

We want to find the number of odd integers from 10 to 51.

The first odd integer from 10 to 51 is 11; the second is 13; the third is 15; and so on until 51. So, our list looks like this:

11, 13, 15, ... , 51

We need to figure out how many numbers there are. Let's add 1 to all of them:

11 + 1, 13 + 1, 15 + 1, ... 51 + 1

12, 14, 16, ... , 52

Now, let's divide by 2:

12/2, 14/2, 16/2, ... 52/2

6, 7, 8, ... , 26

Finally, subtract 5 from them:

6 - 5, 7 - 5, 8 - 5, ... , 26 - 5

1, 2, 3, ... , 21

There are 21 odd integers, so x = 21.

The even integers from 10 to 51 start with 12, 14. They end with 50. So, we have:

12, 14, ... 50

Let's use a similar method as above. Divide by 2:

12/2, 14/2, ... , 50/2

6, 7, ... , 25

Subtract 5:

6 - 5, 7 - 5, ... , 25 - 5

1, 2, 3, ... , 20

There are 20 even integers, so y = 20.

Then, x + y = 21 + 20 = 41.

The answer is thus C.

<em>~ an aesthetics lover</em>

8 0
3 years ago
Read 2 more answers
Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42
Licemer1 [7]

Answer:

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

Step-by-step explanation:

Given

x^3y^6 + 27z^{42

Required

Factor

Express both terms as a cube

x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3

Let

a =(xy^2)

b = (3z^{14})

So:

x^3y^6 + 27z^{42} = a^3 + b^3

Using sum of cubes:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

So:

x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)

Substitute in, values of a and b

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

5 0
3 years ago
Read 2 more answers
Help with algebra hw
Minchanka [31]

Answer:

Step-by-step explanation:

6 0
3 years ago
If the mean of a normal distribution is 22, what is the median of the distribution?
DerKrebs [107]

Answer:

22

Step-by-step explanation:

Normal Distributions are the most important in statistics. They are also know as "bell curves".

There are special properties of Normal Distributions. I name 3 of them below:

1. Normal distributions are symmetric about their mean.

2. The area under the normal curve is 1

3. The mean, mode, and median of normal distribution are equal

This question can easily be solved using property #3 in the stated above properties.

The mean and median of normal distribution are equal. Since mean is given as 22, the median will also be 22.

8 0
4 years ago
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