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Alla [95]
2 years ago
11

Jackie starts walking at the beginning of a trail that is 1.6 miles long and walks to the end.

Mathematics
1 answer:
Reptile [31]2 years ago
4 0

Answer:

C

Step-by-step explanation:

Multiply first to find how far she walked

Divide to find how many 0.5 are in the distance

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PLEASE HELP!!!
Veronika [31]

The quotient is defined and rational,
but it's not an integer.

It's  -1/11 .

8 0
4 years ago
Read 2 more answers
Solve the equation. Round to the nearest hundredth. Show work.
Elis [28]

Answer:

The value of x = 0.41

Step-by-step explanation:

∵ 6e^{2x}-5e^{x}=6

Let e^{x}=y

∴ e^{2x}=y^{2}

∴ 6y² - 5y = 6

∴ 6y² - 5y - 6 = 0 ⇒ factorize

∴ (3y + 2)(2y - 3) = 0

∴ 3y + 2 = 0 ⇒ 3y = -2 ⇒ y = -2/3

∴ 2y - 3 = 0 ⇒ 2y = 3 ⇒ y = 3/2

∵ y=e^{x}

∴ e^{x}=\frac{-2}{3} ⇒ refused

  (e^{ax} never gives -ve values)

∵ e^{x}=3/2 ⇒ insert <em>ln</em> in both sides

∵ lne^{ax}=axlne=ax ⇒ <em>ln</em>(e) <em>= 1</em>

∴ xlne=ln(3/2)

∴ x = ln(3/2) = 0.41

6 0
4 years ago
Sara's paper airplane flew 8 1/2 yards. Jason's flew 8 2/3 yards. Michael's flew 8 1/4 yards and Denise's flew 8 1/6 yards. whos
nirvana33 [79]
Jason's airplane flew the farthest. When you find a common denominator for all the fractions, 8 2/3 is the largest,
Sara = 8 6/12
Jason = 8 8/12,
Michael = 8 3/12,
Denise = 8 2/12,

6 0
4 years ago
Hunter has a total of $9.60 in dimes and nickels. Let d be the number of dimes and n be the number of nickels.
andrezito [222]

Answer:

58

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
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