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Bogdan [553]
3 years ago
7

15 liters increased by 60% is liters

Mathematics
2 answers:
fomenos3 years ago
8 0
15 times .6 is 9
add that to 15 since your increasing by 60 percent
24
NemiM [27]3 years ago
3 0
(15*.6)+15=24 liters
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A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious
Dominik [7]

Answer:

Part1) z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

p_v =2*P(Z>2.191)=0.0284

Readjustment is needed

Part 2)  z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

p_v =2*P(Z

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1    

\bar X=16.32 represent the sample mean    

\sigma=0.8 represent the population standard deviation    

n=30 sample size    

\mu_o =16 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu =16    

Alternative hypothesis :\mu \neq 16    

Compute the test statistic  

The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z>2.191)=0.0284

Using the value of \alpha =0.05 we see that pv and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)    

Part 2

\bar X=15.82 represent the sample mean    

We can replace in formula (1) the info given like this:    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z

Using the value of \alpha =0.05 we see that pv>\alpha and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)  

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0
4 years ago
Heather Pablo, and Shen sent a total of 123 text messages during the weekend. Heather sent 9 more messages than Pablo. Shen sent
Korolek [52]

Answer:

Heather sent 28, Pablo sent 19, and Shen sent 76.

Step-by-step explanation:

This will be your equation

123 = H (Heather) + P (Pablo) + S (Shen)

This is the extra stuff

P + 9 = H

4P = S

Substitute so there is only P then use that to solve for the rest

123 = P + 9 + P + 4P

Then solve

123 = 6P + 9

123 - 9 = 6P + 9 - 9

114 = 6P

19 = P

Then substitute for the extra equations

19 (P) + 9 = 28 (H)

19 (P) * 4 = 76

8 0
3 years ago
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Naily [24]
I don’t have the time for my birthday but I’m just asking for a little
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3 years ago
What are the coordinates of the image of vertex G after a reflection across the line y = x? (–4, –5) (4, 5) (–5, 4) (5, –4)
Sergio039 [100]

Answer:(-5,4)

Step-by-step explanation:

Just took the test on edge

4 0
3 years ago
Five times the sum of a number and one is 115. What is the number? Use x as your variable.
ollegr [7]
The initial equation is:
5(x+1)=115

Let's transform it for x:
5x+5=115

... distract 5:
5x=110

... divide both sides by 5:
x=22
7 0
3 years ago
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