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uysha [10]
3 years ago
5

What is an equation of the line that passes through the points (6, 5) and (6, -7)?​

Mathematics
1 answer:
zvonat [6]3 years ago
3 0

Answer:

If a line is parallel to another line they’ll have the same slope. We can figure out the slope by taking the given equation of a line and changing it to slope-intercept formula.

x + 3y = 15

3y = -x + 15

y = -1/3 x + 5

Now we know the slope of our line is -1/3. We can use this and the given point to calculate our y-intercept, commonly known as b in the slope-intercept formula.

-5 = -1/3 (-6) + b

-5 = 2 + b

-7 = b

Now that we know our slope, m, and our y-intercept, b, we can write the equation of the line.

y = mx + b

y = -1/3 x - 7

Step-by-step explanation:

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Combine the like terms to create an equivalent expression:<br> -2x-x+8
lara31 [8.8K]

Answer:

-3x+8

Step-by-step explanation:

-2x-x+8=

-3x+8

7 0
3 years ago
Sasha spins a spinner with 2 happy face sections, 1 sad face
cricket20 [7]

Answer:

Step-by-step explanation:

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6 0
3 years ago
Consider the system of equations given in slope-intercept form. y = −13x + 17, y = 5x - 23 The solution seems to be about (8, 14
bogdanovich [222]

Answer:

The exact solution for this equation would be (2.222, -11.889)

Step-by-step explanation:

Since it told us to use a graphing calculator, I went on to desmos graphing calculator, typed in the equation, then I found out where the two line intersect, and then that was the answer.

4 0
4 years ago
Read 2 more answers
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chubhunter [2.5K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
A ball travels on a parabolic path in which the height (in feet) is given by the expression $-25t^2+75t+24$, where $t$ is the ti
evablogger [386]

Answer:

The height of the ball is at it's maximum 1.5 units of time after launch.

Step-by-step explanation:

Suppose we have a quadratic function in the following format:

h(t) = at^{2} + bt + c

If t is negative, the maximu value of h(t) will happen at the point

t_{MAX} = -\frac{b}{2a}

In this question:

h(t) = -25t^{2} + 75t + 24

So

a = -25, b = 75, c = 24

Then

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The height of the ball is at it's maximum 1.5 units of time after launch.

8 0
3 years ago
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