Answer:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
Step-by-step explanation:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.
I am joyous to assist you anytime.
Answer:
39V3 Sq.units of that will help you
Answer:
See below
Step-by-step explanation:
Remember that quadratic functions are parabolas when graphed. The solutions are where the parabola crosses the x-axis.
1. The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up. So the parabola does not cross the x-axis. Therefore the solutions are imaginary.
2. The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up. Therefore, there is a double solution.
3. The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up. Therefore, there are two real solutions.
I know this is a long explanation, but that is a way of looking at the problem.
Answer:
I think it's the last one. Sorry if I'm wrong
16 1/10
Because you have 15 and then for 22/20 it is a improper fraction so take 20 away from it to get 2/10 then add 1 to 15 for 16 and then simplify 2/20 to 1/10