The vertices of quadrilateral ABCD are given. Draw ABCD in a coordinate plane and show that it is a parallelogram.
1 answer:
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Answer:
acute
Step-by-step explanation:
Given the 3 sides of a triangle a, b, c ( where c is the longest )
• If a² + b² = c² ⇒ right triangle
• If a² + b² > c² ⇒ acute angled triangle
• If a² + b² < c² ⇒ obtuse angled triangle
Here a = , b =
, c = 4
c² = 4² = 16
a² + b² = ( )² + (
)² = 11 + 7 = 18
Since a² + b² > c² then triangle is acute
Answer:
Option (7)
Step-by-step explanation:
5x + 6y > 1
6y > -5x + 1
y >
y-intercept of the line =
Shaded area will be above the dotted line y =
y - x < 0
y < x
As y-intercept of the line is zero, given inequality will pass through (0, 0).
And the shaded area will be below the line.
Therefore, graph shown in Option (7) will be the correct option.