Solve the inequalities by graphing. Identify the graph that shows the following equations.
1 answer:
Answer:
Option (7)
Step-by-step explanation:
5x + 6y > 1
6y > -5x + 1
y >
y-intercept of the line =
Shaded area will be above the dotted line y =
y - x < 0
y < x
As y-intercept of the line is zero, given inequality will pass through (0, 0).
And the shaded area will be below the line.
Therefore, graph shown in Option (7) will be the correct option.
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-17 + n/5 = 33
First, we can start out by regrouping our terms. This will switch our fraction and number around and also make the original addition to subtraction.
Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.
Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.
Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.
Fifth, our last step is to multiply 50 × 5. Use a calculator, long multiplication, etc. 50 × 5 = 250.
Answer:
First, we can start out by regrouping our terms. This will switch our fraction and number around and also make the original addition to subtraction.
Second, we can start out our goal by trying to get the variable (n) on one side by itself and to equal something. Let's begin by adding 17 to each side of the problem.
Third, we can now add the numbers on the right side of our problem. Simple. Add 33 + 17 to get 50.
Fourth, we now have to multiply both sides by 5. Why? We are getting rid of the fraction so that the variable can become by itself.
Fifth, our last step is to multiply 50 × 5. Use a calculator, long multiplication, etc. 50 × 5 = 250.
Answer:
Answer
The mean of three numbers x1,x2,x3 can be obtained by a calculus. The first step of the algorithm is
1)
In order to obtain the median, maximun and minumun of x1, x2 and x3, we can compare x1 and x2. The smaller of those numbers will be compared to x3 and, if x3 is even smaller, then x3 is the minimun, the other small number is the median, and the remaining number is the maximun. Otherwise, we compare x3 with the bigger number to find median and maximun. To summarize:
2) compare x1 with x2. The bigger of the two numbers will be called '<em>s</em>' (for small) and the smaller will be called '<em>b</em>' (from big).
3) compare x3 with <em>s</em>. The smaller of this subset will be the minimun of the entire set of 3 elements.
4) Check if x3 is the minimun, in that case, <em>s </em>is the median, because <em>s</em> is between x3 and <em>b. </em>We also conclude that <em>b</em> is the maximun
5) if x3 in not the minimun, then compare it with <em>b.</em> The bigger element between the two of them will be the maximun of the set, and the smaller one will be the median.
I hope it helps you!