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Oduvanchick [21]
3 years ago
9

Can u help pleaseeeeeeee

Mathematics
2 answers:
liraira [26]3 years ago
6 0
24??? Hehehehe hope it helpsss
Trava [24]3 years ago
5 0

Answer:

24

Step-by-step explanation:

∆ABC = ∆XYZ

line AB = line XY

3 = 18

18 ÷ 3

= 6

if you divide 36(line YZ) by 6(line BC), you'll also get 6

therefore, 4×6 = 24

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Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)
Elan Coil [88]

Answer:

10u^{3}+4u^{2}-2u+10 or 2(5u^{3}+2u^{2}-u+5)

Step-by-step explanation:

we have

(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)

step 1

Group terms that contain the same variable

(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)

step 2

Combine like terms

(10u^{3})+(4u^{2})+(-2u)+(10)

step 3

Eliminate parenthesis

10u^{3}+4u^{2}-2u+10

step 4

Factor the number 2

2(5u^{3}+2u^{2}-u+5)

8 0
3 years ago
Read 2 more answers
If you vertically stretch the absolute value parent function, f(x) = [xl, by a
fgiga [73]

Answer:

g(x) = 5|x|

Step-by-step explanation:

Given

f(x) = |x|

b =5 --- vertically stretch

Required

The new function

The rule for vertical stretch is:

g(x) = bf(x)

So, we have:

g(x) = 5 * |x|

g(x) = 5|x|

4 0
3 years ago
In math class, the girl to boy ratio is 8 to 6. If there are 24 girls in the class, how many boys are there?
Studentka2010 [4]

Answer:

8 : 6 = 24 : 18

Step-by-step explanation:

If there were 24 girls in class, there would be 18 boys.

Girls: 8, 16, 24

Boys: 6, 12 , 18

4 0
3 years ago
Read 2 more answers
In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t
Basile [38]

So, since averages are defined as:

\frac{\sum_{k=1}^{P} P_k}{P}=70

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

\frac{\sum_{k=1}^{N} N_k}{N}=70

We can take both of these equations and multiply them by N:

\sum_{k=1}^{P} P_k=70P

\sum_{k=1}^N N_k=92N

So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}

Simplified we would have P/N=3/8.

7 0
3 years ago
What is the cooeffeciant in the expression shown below 42+2c
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The coefficiant in the expression is the "c" next to the 2 
6 0
3 years ago
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