Answer:
Step-by-step explanation:
I can't make specific statements about the proof because the midpoint is missing.
Givens
There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.
MN is bisected by the point on MN where the perpendicular meets MN
The Perpendicular Bisector is is common to both triangles.
Therefore the two triangles are congruent by SAS
PM = PN Parts contained in Congruent triangles are congruent.
Answer:
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
Step-by-step explanation:
(f-g)(x) = x^4 - x^2 + 9 - (x^3 + 3x^2 + 12)
(f-g)(x) = x^4 - x^2 + 9 - x^3 - 3x^2 - 12
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
No its a negitive number one x minus five x's equal -14
