PLEASE HELP!!!!! I don’t get it all :((((

A manufacturing process makes rods that vary slightly in length but follow a normal distribution with mean length 25 cm and stan

Galina-37 [17]

Answer:

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22) = 0.1251

Step-by-step explanation:

Step(i):-

Given mean of the Population = 25cm

Given standard deviation of the Population = 2.60

Let 'x' be the random variable in normal distribution

Given x=22

$Z = \frac{x-mean }{S.D} = \frac{22-25}{2.60} = -1.15$

Step(ii):-

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22) = P( Z<-1.15)

= 1-P(Z>1.15)

= 1-( 0.5+A(1.15)

= 0.5 - A(1.15)

= 0.5 - 0.3749

= 0.1251

The probability of randomly selecting a rod that is shorter than 22 cm

P(X<22) = 0.1251

7 0

3 years ago

PLEASE HELP Complete the table with the number of sit-ups you have to do sunday so that the mean number of sit-ups per day is 10

klemol [59]

The complete table will be:

$Monday - 100\\ Tuesday-65\\ Wednesday- 120\\ Thursday-150\\ Friday-90\\ Saturday- 0\\ Sunday-175$

Explanation

Suppose, the number of sit-ups in Sunday is $x$

Mean is the simple average of some numbers. For finding the mean number of sit-ups per day, we need to divide the 'total number of sit-ups' by the 'total number of days'.

Here the total number of days is 7 and the total number of sit-ups for 7 days $= 100+65+120+150+90+0+x= 525+x$

Given that, the mean number of sit-ups per day is 100. So, the equation will be...

$\frac{525+x}{7}=100\\ \\ 525+x=700\\ \\ x= 700-525=175$

So, the number of sit-ups you have to do Sunday is 175.

6 0

3 years ago

In the number 7,890,432, name the digit located in each of these positions.

alina1380 [7]

A=4 B=7 C=9 D=3 E=8 F=0

3 0

3 years ago

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The vertices of triangle rst are r(–1,–2), s(2,–1), and t(4,2). If δjkl ∼ δrst and the length of kl is units , what is the lengt

NemiM [27]

Answer:

3.16 units

Step-by-step explanation:

It has been given that the triangles JKL and the triangle RST are congruent.

That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.

Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are $(-1,-2)$ and $(2,-1)$ .

The length of the side RS is equal to the distance between point R and S.

RS $=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$= \sqrt{(2-(-1))^2+(-1-(-(-2))^2}$

$=\sqrt{3^2+(-1+2)^2}$

$=\sqrt{9+1}=\sqrt{10}=3.16$

Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.

7 0

3 years ago

Read 2 more answers

PLEASEHELP!

denis-greek [22]

You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0

3 years ago