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2 years ago

PLEASE HELP!!! Find the sum of all solutions to the equation 4x(x-3) = 23.

1 answer:

7 0

I think it’s -3 because I’m guessing you have to times the 4x with the number inside the parenthesis so it would be 4x-12x = 23 and 4-12 is -8 = 23 and 23 divided by -8 is -3

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Let the function f be continuous and differentiable for all x. Suppose you are given that f(−1)=−3, and that f'(x) for all value

Monica [59]

Answer:

Step-by-step explanation:

By MVT,

$f'(c) = \frac{f(5)-f(-1)}{5-1}$

$4f'(c)= f(5) + 3\rightarrow f(5) = 4f'(c) - 3$

Moreover, $f'(x)\leq 4~~~~~~ \forall x,$

$f(5) \leq 16 - 3 =13$

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2 years ago

Which expression is equivalent to (x^4/3 x^2/3)^1/3?

KATRIN_1 [288]

Answer: $x^{\frac{2}{3} }$

Step-by-step explanation:

We have several properties of exponents in use here. The two that are used are:

$(x^{a})(x^{b}) = x^{a + b}$ (Exponents with the same base that are being multiplied together can have the exponents added)

$(x^{a})^{b} = x^{(a)(b)}$ (A base raised to a power, and then raised to another power means that you can multiply the exponents to get the same result as doing inside operations and then outside operations)

Let's apply it!

First, let's simplify what's inside the parenthesis.

$x^{\frac{4}{3} } x^{\frac{2}{3} }$ (Remember, they have the same base of "x", so we can add the exponents)

$x^{\frac{4}{3} + \frac{2}{3} }$ = $x^{\frac{6}{3} }$ = $x^{2}$

Now we have $(x^{2})^{\frac{1}{3} }$ . Let's use the second rule.

$(x^{2})^{\frac{1}{3} }$ = $x^{\frac{2}{3} }$

Hope this helps! :^)

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2 years ago

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AveGali [126]

200/3.8= 52.6 mph
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