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mote1985 [20]
2 years ago
13

For how many different digits n is the two-digit number 6n divisible by n? (The expression 6n should be interpreted as a two-dig

it integer with tens digit 6 and units digit n, not as 6 times n.)
Mathematics
2 answers:
dalvyx [7]2 years ago
6 0

Answer:

6 values n

Step-By-Step Explanation:

If n  =1        then    6n    =  61    

n  =2                           =  62    

n = 3                          =   63    

n = 4                          =   64    

n = 5                         =    65    

n = 6                         =    66    

These are the only ones that work [ 67/7 , 68/8, 69/9 and 60/0 are not integers  (the last is undefined)]

So.....6 values of  n

natita [175]2 years ago
5 0

Answer:

ewfewfgregergergreg

Step-by-step explanation:

regergregrerg

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5 is 20% of what number
Georgia [21]
Five is twenty % of twenty-five
3 0
4 years ago
11. How else can the ratio 14:1 be written?
solmaris [256]
14:1 can also be written as 14 to 1 and 14/1. Aka 14/1 is in fraction form not division.
5 0
3 years ago
Find the distance between the points (-3, 9) and (6,-5). Round the answer to the nearest tenth.
inna [77]

Answer:

D. 16.6

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-3,9)

(x_2,y_2) = (6,-5)

Replacing these values in the distance formula

D =\sqrt{(-3-6)^2+(9-(-5))^2}

D =\sqrt{(-9)^2+(9+5)^2}

D =\sqrt{(-9)^2+(14)^2}

D =\sqrt{81+196}

D =\sqrt{277}

D= 16.6433

Hence the Distance is 16.60 units

6 0
4 years ago
The length and breadth of a rectangle are in a 15 : 11 ratio. If the length is 56 cm more than the breadth, find the perimeter o
tensa zangetsu [6.8K]

Answer:

g

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Linear Algebra: Permutation Matrices Let M be the matrix {{0,0,0,1,0}, {0,0,1,0,0}, {0,1,0,0,0}, {0,0,0,0,1}{1,0,0,0,0}}. What i
FromTheMoon [43]

Multiplying M by any matrix A would return new matrix, B, in which

• the 1st row of B is equal to the 4th row of A,

• the 2nd row of B is equal to the 3rd row of A,

• the 3rd row of B is equal to the 2nd row of A,

• the 4th row of B is equal to the 5th row of A, and

• the 5th row of B is equal to the 1st row of A.

The pattern here is

1 => 4 => 5 => 1

2 => 3 => 2

Let {4, 3, 2, 5, 1} denote the matrix M, where each number refers to the row of the identity matrix, I.

Using this notation, the pattern above gives

M² = {5, 2, 3, 1, 4}

M³ = {1, 3, 2, 4, 5}

M⁴ = {4, 2, 3, 5, 1}

M⁵ = {5, 3, 2, 1, 4}

M⁶ = {1, 2, 3, 4, 5}

so that <em>n</em> = 6.

(Notice that the first cycle has length 3 and the second one has length 2; the minimum <em>n</em> needed here is then LCM(2, 3) = 6.)

6 0
3 years ago
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