Use a graph to slove the equation 2x+3=4

Mathematics

1 answer:

ANTONII [103]2 years ago

5 0

Answer:

x=0.5=1/2

Step-by-step explanation:

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i need help with this questions asap please. A grocery clerk is making a display of oranges. The numbers of oranges in the layer

ahrayia [7]

Answer:

If there is 1 at the top, then you have 1, then 2, then 3, etc.

total number of oranges equals:

1 + 2 + 3 + ... + 16 + 17 + 18 <-- stop at 18 because this is the number of oranges at the base

You can use the formula:

sum of first n numbers = n*(n + 1)/2

-->

18*19/2 = 9*19 = 171

or you can figure it out (basically derive the above formula):

you have:

1 + 18 = 19

2 + 17 = 19

3 + 16 = 19

...

How many pairs do you have? Well, it's just the number of numbers: 1-18 = 18 numbers (divide by 2) = 9 pairs)

9 pairs of 19 = 9 * 19 = 171

Hope this helps!

Step-by-step explanation:

3 0

3 years ago

-(3/4)+1 7/8 divided by 1/2 =n

VashaNatasha [74]

first off, let's convert the mixed fraction to improper fraction and then proceed, let's notice that by PEMDAS or order of operations, the multiplication is done first, and then any sums.

$\stackrel{mixed}{1\frac{7}{8}}\implies \cfrac{1\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{15}{8}} \\\\[-0.35em] ~\dotfill\\\\ -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \div \cfrac{1}{2}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{8} \cdot \cfrac{2}{1}\implies -\cfrac{3}{4}~~ + ~~\cfrac{15}{4} \\\\\\ \cfrac{-3+15}{4}\implies \cfrac{12}{4}\implies 3$

5 0

2 years ago

Solve the system of linear equations. separate the x- and y- values with a coma.

kobusy [5.1K]

Solve the following system:
{7 x - 3 y = 37 | (equation 1)
{14 x + 11 y = 23 | (equation 2)
Swap equation 1 with equation 2:
{14 x + 11 y = 23 | (equation 1)
{7 x - 3 y = 37 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x + 11 y = 23 | (equation 1)
{0 x - (17 y)/2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:
{14 x + 11 y = 23 | (equation 1)
{0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:
{14 x + 11 y = 23 | (equation 1)
{0 x+y = -3 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{14 x+0 y = 56 | (equation 1)
{0 x+y = -3 | (equation 2)

Divide equation 1 by 14:
{x+0 y = 4 | (equation 1)
{0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 4
{y = -3